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Kirchoff's Laws.

Fundamental Series FS02 - November, 2005


Kirchoff's Laws.

Sometime called Kirchhoff's Current or Junction Law, Kirchoff's 1st Law states:

The sum of the currents entering a node must equal the sum of the currents exiting a node - or stated differently, the algebraic sum of all the currents entering any node must be zero.

Kirchoff's 2nd law, sometimes call Kirchoff's Voltage or Loop Law, states:

The algebraic sum of the voltage voltages around a closed path in a circuit is zero.


Notes:

Biography and Backgound

Gustav Robert Kirchoff was a German physicist born in 1824 in Konigsber, Prussia. The son of a lawyer that had a strong sense of duty to the Prussion state, Gustav was brought up to believe that someone with his intellectual abilities should become a university professor.

Educated at the Albertus University of Konigsberg he was heavily influenced by his mathematical physics professor Franz Neumann and later his mathematics professor Friedrich Richelot.

While he was studying with Neumann, Kirchhoff formulated his first research theories on the conduction of electricity. Building upon the work of Ohm’s, in 1845 Kirchhoff published his Laws of Closed Circuits that apply to all electric circuits. His observations and deductions led to the method of calculation of current, voltage and resistance in electrical circuits with multiple loops. Kirchhoff was the first to formulate the correct understanding of the theory of how electric currents and electrostatics should be combined.

Although Kirchhoff’s laws have immortalized him in the field of Electrical Engineering, Kirchhoff also had additional discoveries.-- He was the first person to record and verify that an electrical impulse travels the speed of light. Kirchhoff also made significant contributions in the study of the spectrum of light as well as blackbody radiation

Kirchoff died in Berlin on October 17, 1887.


Kirchoff's 1st Law states:

The algebraic sum of all the currents entering any node must be zero.

In Figure 1, Kirchoff's current law is shown. The sum of all the currents entering the the node must be zero. If we know any two of the three currents shown, the third can be calculated.



For example, if we know i1 and i2, then:

    i3 = i1 + i2

Kirchoff's 2nd Law states:

The algebraic sum of the voltage voltages around a closed path in a circuit is zero.

In Figure 2, Kirchoff's second law is shown. The sum of the voltages around any of the two closed loops shown will be zero.

This is a definition of the meaning of Potenial. Every point within the loop has a unique potential value. No matter what summation path we take around a closed loop, when we return to the starting point of the path, the potential must be exactly the same as we began.

There is a third loop not shown in the figure, it is the outer loop which circles the two inner loops shown.

Applying Kirchoff's Voltage law to the outer loop we find that:

-v1 + R1×i1 + R3×i2 + R4×i2 + R5×i2 + R6×*i1 = 0

Although these Laws may appear to be simple, they are powerful analytical tools, and form the basis for complex mesh analysis of the most complex circuits.

Gustav Kirchhoff
(1824-1887)

An Example.


Figure 3 shows a simple circuit. Applying Kirchoff's Voltage Law, we get:

-v1 + R1×i1 + R2*i1 = 0 or i1×(R1 + R2) = V1 and i1 = V1÷(R1 + R2)

From Ohms's Law if the voltage vR2 across R2 is i1×R2, then substituting the above for i1 we get

vR2 = V×(R2)÷(R1 + R2)

Which is the familar voltage divider formula.



A more complex example.


Figure 4 shows a more complex dual mesh circuit. We want to solve for the value of current i1. From Ohms's Law, we know that the voltage accross a resistor is i×R. Applying Kirchoff's Voltage Law, we get two equations:

-v1 + 10×(i1) + 20×(i1-i2) = 0 equ. 1

20×(i2-i3) + 30×(i2)= 0 equ. 2

There are two equations and two unknowns, so we can solve for i1.
First we express i2 in terms of i1. Using equ. 2

20×i2 - 20×i1 + 30×i2 = 0

i2 = (50÷20)×i2

substituting this value into equ. 1

(10)×i1 + (20)×i1 - 20×((20÷20)×i1) = 10

(30)×i1 - (8)×i1 = 10

i1 = 10÷22 = 0.455 and

i2 = (20÷50)×i1 = 0.182

Finally, using Kirchoff First law we can calculate the actual current in the 20ohm resistor, i?. Since the sum of the currents entering the node where all the resistor combined must be zero

i1 - i2 + i? = 0    (i1 is entering, i2 is leaving)

i? = -i1 + i2 = -0.273    (i? is leaving)

To verify our answer, if we combine the parallel the 20 and 30ohm (12ohm combined) resistors in series with the 10ohm resisitor we get we get a value of 22ohms, so the current in the circuit (which is equal to i1) is:

10volts÷22ohms = 0.455

Using the voltage divider equation we derived above, the voltage across the 20 and 30ohm resistors in parallel is:

10volts×(12÷(10+12) = 5.455

and finally using Ohms's Law to find i?

i? = 5.455÷20 = 0.273

In conclusion

These are only just a few examples of applications of Kirchoff's Law's. Kirchoff's Laws are the next things after Ohm's Law that most electrical engineering students learn. Kirchoff's Laws are fundamental to understanding and analyzing circuit and networks no matter how complex.